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Grouping concept.

For every 5 pens sold, another 2 are given free.

The 7 pens here can be counted as 1 group.

Cost of 1 such group = $2 × 5 = $10

He wants to buy 65 pens. How many of such groups can he buy at most?

65 ÷ 7 = 9 R 2

So he can buy 9 groups (9 × 7 = 63 pens) and the remaining 2 pens are bought at individual price.

9 × $10 + 2 × $2

= $90 + $4

= $94 (answer)

For every 5 pens sold, another 2 are given free.

The 7 pens here can be counted as 1 group.

Cost of 1 such group = $2 × 5 = $10

He wants to buy 65 pens. How many of such groups can he buy at most?

65 ÷ 7 = 9 R 2

So he can buy 9 groups (9 × 7 = 63 pens) and the remaining 2 pens are bought at individual price.

9 × $10 + 2 × $2

= $90 + $4

= $94 (answer)

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Date Posted:
1 week ago